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Steven Seagal Height, Weight

Last updated on 01/14/2019 by HowTallis.Org

Steven Seagal Height, Weight

How tall is Steven Seagal?

Steven Seagal’s height is 6ft 4in (193 cm).

How much does Steven Seagal weigh?

Steven Seagal weighs 280-300 lbs (127-137 kg). He was about 190 lbs (86 kg) in Above the Law, 1988 (his first movie).

What is Steven Seagal’s shoe size?

Steven Seagal’s shoe size is 11 US (44 EU).

What is Steven Seagal’s zodiac sign?

Steven Seagal’s zodiac sign is Aries.

When was Steven Seagal born?

Steven Seagal’s birthday is on April 10, 1952.

Where was Steven Seagal born?

Steven Seagal was born in Lansing, Michigan, USA.

American actor and a 7th-dan black belt in Aikido, ethnicity – Jewish (father), Irish (mother), Steven Seagal’s full name is Steven Frederic Seagal.

Related: Actors, Male celebs over 6′ 3″

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Comments

  1. Anonymous

    03/04/2017

    A bit larger now…..say 400#

    Reply

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